Most of the memory used by programs are pointers, and if you double your pointer size, it has a negative impact on the efficientcy of the L1 and L2 cache.
2 comments
Yes, this is exactly what CurtHagenlocher said.
>> Most of the memory used by programs are pointers
This is a huge generalization, may I add.
Yes, I will not argue that cache usage is less efficient, but I am sure you know that register access is faster than cache access, and we double the amount of registers in x64.
>> Most of the memory used by programs are pointers
This is a huge generalization, may I add.
Yes, I will not argue that cache usage is less efficient, but I am sure you know that register access is faster than cache access, and we double the amount of registers in x64.
To quote Donald Knuth, a 64 bit program would "waste half the memory [and] effectively throw away half of the cache".
You may double the number of registers, but you are still shuffling tons of data between your caches and memory, and that is going to be your constraint for most programs. Losing half of the 4mb or 12mb of your L2 or L3 cache because you use 64 bit pointers has a much bigger impact than doubling the number of registers.
You may double the number of registers, but you are still shuffling tons of data between your caches and memory, and that is going to be your constraint for most programs. Losing half of the 4mb or 12mb of your L2 or L3 cache because you use 64 bit pointers has a much bigger impact than doubling the number of registers.