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warbler73

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warbler73
·4 वर्ष पहले·discuss
warbler73
·4 वर्ष पहले·discuss
warbler73
·4 वर्ष पहले·discuss
That is not acceptable.
warbler73
·4 वर्ष पहले·discuss
How does Google "own" this "market"?
warbler73
·4 वर्ष पहले·discuss
Any gTLD whatsoever owned by some for profit corporation is not acceptable.
warbler73
·4 वर्ष पहले·discuss
warbler73
·4 वर्ष पहले·discuss
Why should any TLDs at all, like .dev and .app, be owned by Google?
warbler73
·4 वर्ष पहले·discuss
> domain extensions like .dev and .app are owned by Google

Why are domain extensions like .dev and .app owned by Google?
warbler73
·4 वर्ष पहले·discuss
[flagged]
warbler73
·4 वर्ष पहले·discuss
warbler73
·4 वर्ष पहले·discuss
warbler73
·4 वर्ष पहले·discuss
[flagged]
warbler73
·4 वर्ष पहले·discuss
warbler73
·4 वर्ष पहले·discuss
warbler73
·4 वर्ष पहले·discuss
Why do you think people without passports (or uncomfortable uploading government documents to nearly every website they wish to use) should not be allowed to use those websites.
warbler73
·4 वर्ष पहले·discuss
> Most people satisfy the "two forms of identification" requirement

53% of US adult citizens have a passport as of 11/22. Most of them have a state ID as well. So yes, a bare majority of citizens will be allowed internet access.

I have never seen a library card or insurance card with a photo id that is accepted as id at all, much less valid id. Do you have examples and if so how common is this in Texas?
warbler73
·4 वर्ष पहले·discuss
"Man's got a point. Two is no good. Let's make it three photo ids." - Texas Legislator Tex

"Hole up there son, we don't want to have to revisit this every year to patch holes. Let's put in a safety margin: Five photo ids." - Texas Legislator Champ
warbler73
·4 वर्ष पहले·discuss
> This might not only be about protecting the children.

When you have verified name and address of every user you can charge a lot more for ads.
warbler73
·4 वर्ष पहले·discuss
Uh oh. Is it that obvious?
warbler73
·4 वर्ष पहले·discuss
I like to roll this way! (Just not at work.)

    SELECT
      employee_name
    , company_name
    , salary
    , state_code
    , city
      FROM 'employees';