How to segfault bash: a() { a; }; a

Just wait a bit and you will get a SEGV error

3 comments

dozzie9 anni fa

It's not a surprising result. You just run out of stack with your infinite recursion, and shells usually don't perform tail call optimization.

So does

    :(){ :|: & };:

bbcbasic9 anni fa

Cousin of fork bomb?