A 400 V DC setup is common for this sort of application, so:
667 kW / 400 V = 1667 A
How physically large do the cables and related apparatus need to be in order to deliver this sort of current? What sort of training and personal protective equipment will people need in order to plug and unplug these cables? (Hint: Arc flashes are no joke!) What sort of service would you need to order from the electric company to be able to power just one of these installations?
80 kWh / 0.8 = 100 kWh
To charge in nine minutes:
100 kWh * 60 min/hr / 9 min = 667 kW
A 400 V DC setup is common for this sort of application, so:
667 kW / 400 V = 1667 A
How physically large do the cables and related apparatus need to be in order to deliver this sort of current? What sort of training and personal protective equipment will people need in order to plug and unplug these cables? (Hint: Arc flashes are no joke!) What sort of service would you need to order from the electric company to be able to power just one of these installations?