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lzralbu

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lzralbu
·2 anni fa·discuss
Note that $A_k = \left[\frac{1}{k}, \frac{2}{k}\right] \times \left[\frac{1}{k}, \frac{2}{k}\right] \to \{(0, 0)\}$ in $[0,1]\times [0, 1]$ with the Hausdoff metric, so it is a Cauchy sequence in $X = (0,1) \times (0, 1)$ but without convergent subsequence, i.e., $F(X)$ is not complete, hence not compact so the finite subcover argument fails.
lzralbu
·2 anni fa·discuss
hocus.
lzralbu
·3 anni fa·discuss
The geometric algebra over linear algebra people vs the tau over pi crowd. The two at 80km/h, who is faster?
lzralbu
·3 anni fa·discuss
There's also https://moonscript.org/(Lua's CoffeeScript on author's words).