maththrowaway·15 anni fa·discuss> Also, mathematicians agree in this, seriously. Go and ask one.As an erstwhile mathematician, I don't know of anyone who would suggest that -e^(i pi) is defined as 1. It falls out, rather elegantly, from the definitions of the constants involved.
As an erstwhile mathematician, I don't know of anyone who would suggest that -e^(i pi) is defined as 1. It falls out, rather elegantly, from the definitions of the constants involved.