nmmnthrowaway

3 anni fadiscuss

Yes, but there is a much simpler proof.

3 anni fadiscuss

That is correct. Why are there no others?

3 anni fadiscuss

I think a more interesting problem to consider after solving n^m = m^n is solving n^m = m^n + 1 in the natural numbers.

3 anni fadiscuss

n^n * n^(m - n) = n ^ m = m ^ n, so n^n divides m^n, so n divides m.

comments