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berikv

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How far can I broadcast LoRa packets WITHOUT a radio?

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1 ポイント·投稿者 berikv·12 か月前·0 コメント

コメント

berikv
·2 か月前·議論
Badger Badger Badger originally is a flash animation. To properly archive this, both the flash animation and a machine definition which can run that animation (eg: having a browser with flash plugin) should be stored, not just a video file.
berikv
·9 か月前·議論
“Then there is the % address operator: user %domainB@domainA is first sent to domainA, which expands the rightmost (in this case, the only) percent sign to an @ sign. The address is now user@domainB, and the mailer happily forwards your message to domainB, which delivers it to user. This type of address is sometimes referred to as “Ye Olde ARPAnet Kludge,” and its use is discouraged“
berikv
·昨年·議論
Please don’t terrify your contractors. They fix your place, and you want them on your side doing a good job.
berikv
·昨年·議論
This should be my new screensaver
berikv
·昨年·議論
Also: Fix every bug twice: Both the implementation and the “call site” — if at all possible
berikv
·昨年·議論
Personally, I’d start with divide and conquer. If you’re working on a relevant code base chances are that you can’t learn all the API spec and documentation because it’s just too much.
berikv
·2 年前·議論
Correcting the correction:

> When you connect 2 9000 mAh cells in series, the resulting battery has 2x the voltage but the same mAh capacity. In parallel, the battery has the same voltage but 2x the mAh.

The relevant units are:

* Capacity (Q, in mAh, Ah, kWh, etc)

* Power (P, in Watts)

* Voltage (U, in Volts)

* Current (I, in Amperes)

* Duration (t, in mostly measured in hours)

And the relevant formulas are:

* P = U x I or Power equals Voltage(difference) times Current

* Q = P x t or Capacity equals Power times duration

From this we can establish that connecting batteries in series or in parallel will not change their Capacity. When having 13 batteries of 29000mAh, or 29Ah, you have 13 x 29 = 377Ah or 377000mAh. Connecting batteries in series or parallel does make a difference in voltage and current: a string in series will increase the voltage while keeping the current the same (theoretically, in practice you get less than the current of the weakest cell); a parallel setup will increase the maximum current while keeping the voltage the same (again, in theory).
berikv
·2 年前·議論
Same for me. I wanted to contribute, but the amount of dependencies needed to get a local build to run was a major hurdle.
berikv
·2 年前·議論
Except that the argument here was about bass, and the paper shows that age dependent hearing frequency response varies mostly in the mid-high range.
berikv
·2 年前·議論
And you are? The one who deals out the stereotypes?
berikv
·2 年前·議論
Not saying you are wrong, but this is anecdotal. I’d rather try to interpret crash statistics than use my own experience.
berikv
·2 年前·議論
All of this. Plus the exhaust gasses and tire wear pollutants causing early deaths. The noise (bigger) cars make disrupting quiet places like parks and porches, balconies, bedrooms causing stress. The waste of used cars, often being transported to third world countries. Cars kill in so many ways, especially big cars.
berikv
·2 年前·議論
The counterpoint to that article is: US Big Tech could also abide to EU laws and avoid fines altogether.
berikv
·2 年前·議論
Although I like this interview question, it has a big downside. You make the candidate spend quite a lot of effort while you as an interviewer don’t learn much. The answer to “Can this candidate find and fix this bug?” is not necessarily equal to “Is this candidate a good expansion of the team. What do they bring that we need?”
berikv
·2 年前·議論
With AI closing in on general intelligence, using just binary numbers and some calculations, I’m going to place my bet that quantum entanglement is not necessarily for general intelligence.
berikv
·2 年前·議論
T3e is no b4r w1y to w3e t2t w2h l2g w3s t2n to n10e t2m e8e!

> perl -C -pe 's/(\w)(\w+)(\w)/$1 . length($2) . $3/ge'

Or for the less o4e among us, this v5n will only n10e words with l4h six and up:

> perl -C -pe 's/(\w)(\w\w\w\w+)(\w)/$1 . length($2) . $3/ge'

F3l v5n:

perl -C -pe 's/(\p{L})(\p{L}*)(\p{L})/$1@{[length($2)]}$3/g'

N12g w5t i18n w3d n1t b0e c6e, t2s t2s a u1f-8 c8e v5n. I c2l i0t I16r-v1.0

새0로 오0신 모0든 분1께 인3고 싶2다.