Break up Google
apps.bostonglobe.com41 ポイント投稿者 monfrere10 コメント
A: Firmly: "You need to leave. Now."
B: Shoves A's body multiple times until she is in the opposite corner of the room. Presses his lips to her face without hesitation.
I would be mad as A. But if the scenario went more like: A: "I'm tired and it's late. You really gotta go, sorry."
(A and B walk to the door. There is a sofa by the door.)
B: Leans body toward A's.
A: Takes a step back. Is now up against the sofa and the wall.
B: Puts hand on A's shoulder and leans in slowly for a kiss.
A: Refuses kiss.
Here as person A I would simply brush B off as an aggressive suitor, unless the two aggravating circumstances I mentioned above were in play. Please tell me if that is unfair. sigma f(x_1, ..., x_n) = f(sigma x_1, ..., sigma x_n).
But I don't see how this definition can be consistent. For example, let f(a, b) = a - b
g(a, b) = a/a + b/b = 2
x_1 = 5
x_2 = 3
sigma x_1 = x_2
sigma x_2 = x_1
Then according to the formula: sigma f(5, 3) = sigma (5 - 3) = sigma 2 = f(3, 5) = -2
But sigma g(5, 3) = sigma 2 = g(3, 5) = 2
Contradiction?