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lpmay

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228 points·by lpmay·4년 전·41 comments

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lpmay
·2년 전·discuss
I would never have guessed this configuration was so rare. D-sub connectors seem to have more active use in aerospace and defense that you might expect (Until I started working professionally, I always associated them with "old" computers, not high end stuff).
lpmay
·2년 전·discuss
yes sorry, pitch is smaller density is higher
lpmay
·2년 전·discuss
The important distinction is between on-silicon interconnects and off-silicon. On silicon, the interconnect density is much higher so it's feasible to get high bandwidth by having lots of "channels" (wide busses). This becomes less desirable off chip (on the PCB) for many reasons. Some of them are: 1) The interconnect density is much lower, and having such a large bus becomes physically large 2) The bus is larger and less precise, which makes maintaining skew between channels more and more challenging 3) The parasitic capacitance/inductance (i.e. energy storage) of the bus becomes larger as it gets physically larger, meaning each channel needs a relatively large driver circuit (which costs expensive silicon area) and dissipates more power to drive correctly, and even more power if the speed is increased.

Increasing the symbol complexity of each channel does more than just move the bottleneck around, because it allows fewer chip to chip interconnects to carry more data.

I don't work in this regime, but as a layman I'm not convinced using full QAM for on-board chip to chip interconnects makes sense. One major advantage you natively have over the RF case is you can be easily coherent (shared clock). Throwing this away to do carrier recovery introduces a lot of complexity and potentially reduces the available bandwidth. Assuming you transmit without a carrier, can you have "baseband" QAM without a separate I and a Q signal? If you transmit an I and Q signal separately, does that not just become the same thing as two PAM-32 signals?