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Corun

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The Geometry Junkyard

ics.uci.edu
103 points·by Corun·4 jaar geleden·14 comments

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Corun
·2 jaar geleden·discuss
Those look like pretty normal numbers in my experience. Certainly nothing to worry about. But, the effectiveness of your marketing isn’t necessarily a good measure of your idea and product. Different targeting can change those numbers drastically.

Also, how good web or search ads are really depends on the economics of your product. If your customers will be paying $60 per year then paying 5$ to acquire them is pretty damn good.

For the moment though, I would focus on getting into real conversations(phone or video) with your customers to understand what they want, how much they’d pay, etc. With so much competition for attention, the days of validating with a landing page may be over.
Corun
·3 jaar geleden·discuss
Knowing powers of two in your head (as I guess many of us do) can helps with root estimates and this algorithm.

Take an example sqrt(5819): That's between two powers of two 2^12 = 4096 and 2^13 = 8192. The square roots of those numbers are easy, since you just half the exponent sqrt(4096) = 2^6 = 64

That gives us our initial estimate g for the algorithm from the article. Now we do: b = n / g = 5819 / 64 To do this division in our head we remember that we already know 4096 is 64 x 64. So we just need the remainder (5819 - 4096) / 64 ~= 1700 / 64. Now that's low enough that I can approximate it in my head 64 * 30 is too high by about 3 * 64 so the answer should be around 27 (actual answer 26.5). So b = 64 + 27 = 91

So now we finish the algorithm, sqrt(5819) ~= g + b / 2 = (64 + 91 / 2) = 77.5.

So, how did we do?

The actual sqrt is 76.28, so seems pretty good!