ztorkelson·3 lata temu·discuss> Given a long-term token, can I create short-term, auto-expiring tokens?I suspect the answer is: yes, via attenuation. :)
ztorkelson·4 lata temu·discussIs (non-)determinism really the right concern here? I’m aware that most hash tables do not have generally predictable iteration orders, but I nevertheless understood them to be deterministic.