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gunnihinn

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gunnihinn
·há 5 meses·discuss
The bravery of the people signing this anonymously is inspiring.
gunnihinn
·há 5 meses·discuss
> Terrence Tao was a good example of what happens when an exceptionally smart person stops getting funded by an American University: not moving to another country, but got VC money and created a new company.

What company did Tao fund with VC money?
gunnihinn
·há 6 meses·discuss
[flagged]
gunnihinn
·há 11 meses·discuss
Thanks, I hate it.
gunnihinn
·ano passado·discuss
Their boss does nazi salutes at political events. They’re nazis.
gunnihinn
·ano passado·discuss
I think the Icelandic data is a bit skewed upwards. It’s showing senior and principal level salaries in large companies, most “normal” devs earn maybe 70% of that.
gunnihinn
·há 2 anos·discuss
That's pretty cool. Unfortunately school holidays mean I can't take time off whenever, but I can definitely use the idea to plan time off around those.
gunnihinn
·há 2 anos·discuss
A distribution is not a function. It is a continuous linear functional on a space of functions.

Functions define distributions, but not all distributions are defined that way, like the Dirac delta or integration over a subset.
gunnihinn
·há 2 anos·discuss
For any smooth function (like the conjugate) it makes sense to ask whether there exist holomorphic functions that approximate it arbitrarily well.

However: Suppose that for every n > 0 there exists a holomorphic function f_n such that |f_n(z) - z| < 1/n for all z. Then |f_n(z)| <= |f_n(z) - z| + |z*| = |z| + 1/n by the triangle inequality. A consequence of Liouville's theorem is that any entire holomorphic function with polynomial growth is a polynomial; here in particular we would need to have f_n(z) = a_n z + b_n for some complex numbers a_n and b_n. For real x we would have |(a_n - 1)x + b_n| < 1/n for all x, so a_n = 1. For imaginary iy we would have |(a_n + 1)iy + b_n| < 1/n for all y, so a_n = -1, which is a contradiction.

In fact, if a sequence of holomorphic functions converges uniformely on compact sets, the limit is itself holomorphic because of Cauchy's theorem.
gunnihinn
·há 4 anos·discuss
> 103 Bits of Advice I Wish I Had Known

Not one of them being "edit your writing".