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The Elegant Laminar Flow of Moroccan Tea [video]

youtube.com
1 points·by user070223·3 месяца назад·1 comments

Microwave Cruicble

hackaday.com
2 points·by user070223·3 месяца назад·1 comments

Band of Holes

en.wikipedia.org
48 points·by user070223·8 месяцев назад·12 comments

Randomness Testing Guide

random.tastemaker.design
44 points·by user070223·8 месяцев назад·10 comments

comments

user070223
·3 месяца назад·discuss
Teapot spout placed on the bottom where the pressure is highest. The spout shape change from large opening to smaller one. it is curved like an S(and not U) shape(like a river band?) to "straighten" the water getting rid of eddys which can form after the first curve(which you have to have to pour). The spout has a sharp tip which prevent the pot from dripping (ig nobel prize winner, teapot effect) The tea is poured from a high distant to the cup(laminar) which cools the tea and causes the water to splash which traps sand(remember we are in the Sahara) by making a foam along with the green tea saponin molecules which have of it attracted to water and the other repelled. The sugar makes the liquid viscous along the mints' essential oils which keeps the bubbles.
user070223
·3 месяца назад·discuss
Check his YT channel has more videos
user070223
·3 месяца назад·discuss
Another fun use for gum arabic is making watercolor paints, you can do it with your kids sourcing the pigment from different soils. pour water and let the heavy big particle fall to the bottom and source the small ones from the top and mix some ingredients
user070223
·3 месяца назад·discuss
Github hogging cpu when js is turned off
user070223
·4 месяца назад·discuss
Does any JIT/AOT/hot code optimization/techniques/compilers/runtime takes into account whether the branch prediction is saturated and try to recompile to go branchless
user070223
·6 месяцев назад·discuss
Her logic seems reasonable but stating that the fibers "return to their original crinkled state" is missing the fact that the fiber go through the process of spinning to improve tensile strength (as well as the options of making an infinite yarn from finite fibers by twisting them together). regardless to return to original "crinckled state" they need to overcome those forces as well as the forces of the geometry of the knit(on a different scale).

BTW Rayon is also made from cellulose, cellulose II. While Cellulose I(natural) is metastable it can be converted by disolving in lye to a stable form (beta-gllocouse molecolue chain goes from being parallel to being anti parllel which increases the # of hydrogen bonds as well as helping create a more stable 3d structure) which again improve tensile strength and resist wrinkles on a different scale.
user070223
·7 месяцев назад·discuss
Thought Emporium entire channel is a goldmine

Here's another youtuber journey to fix the lactose intolerance by just eating lactose(powdered milk)("prebiotic") which had strains of a bacteria("probiotic" which feasts on the prebiotic) that breaks down lactose survives in the microbiome https://www.youtube.com/watch?v=h90rEkbx95w
user070223
·8 месяцев назад·discuss
Inspired by this post & TF comment I tried symbollic regression [0] Basically it uses genetic algorithm to find a formula that matches known input and output vectors with minimal loss I tried to force it to use pi constant but was unable I don't have much expreience with this library but I'm sure with more tweaks you'll get the right result

  from pysr import PySRRegressor

  def f(n):
      if n % 15 == 0:
          return 3
      elif n%5 == 0:
          return 2
      elif n%3 == 0:
          return 1
      return 0

  n = 500
  X = np.array(range(1,n)).reshape(-1,1)
  Y = np.array([f(n) for n in range(1,n)]).reshape(-1,1)
  model = PySRRegressor(
          maxsize=25,
          niterations=200,  # < Increase me for better results
          binary_operators=["+", "*"],
          unary_operators=["cos", "sin", "exp"],
          elementwise_loss="loss(prediction, target) = (prediction - target)^2",
)

  model.fit(X,Y)
Result I got is this:

((cos((x0 + x0) * 1.0471969) * 0.66784626) + ((cos(sin(x0 * 0.628323) * -4.0887628) + 0.06374673) * 1.1508249)) + 1.1086457

with compleixty 22 loss: 0.000015800686 The first term is close to 2/3 * cos(2pi*n/3) which is featured in the actual formula in the article. the constant doesn't compare to 11/15 though

[0] https://github.com/MilesCranmer/PySR
user070223
·10 месяцев назад·discuss
New Package Manager(apk) WIP

OpenWrt Upgrade Tool. retaining all of your currently installed packages and configuration

They are updating kernels on yearly basis. 6.12 WIP

web interface for mobile. I think there is an unoffical luci package and a native mobile app.

Notification system. WIP

See also https://forum.openwrt.org/t/community-question-what-do-you-w...