GitHub Copilot and the Methods of Rationality (2022)(freshpaint.io)

    # Compute the difference between each element in an array.
    # compute_difference([1, 2, 5, 10]) == [1, 3, 5])

    """
    The file named input in the current directory has a list of numbers in it, one per line. Each number
    indicates the depth of the sea floor scanning outward from a submarine.

    The first order of business is to figure out how quickly the depth increases, just so you know what
    you're dealing with - you never know if the keys will get carried into deeper water by an ocean
    current or a fish or something.

    To do this, count the number of times a depth measurement increases from the previous measurement.
    (There is no measurement before the first measurement.)

    For example, suppose you had the following report:

    199
    200
    208
    210
    200
    207
    240
    269
    260
    263

    In the example above, the changes are as follows:

    199 (N/A - no previous measurement)
    200 (increased)
    208 (increased)
    210 (increased)
    200 (decreased)
    207 (increased)
    240 (increased)
    269 (increased)
    260 (decreased)
    263 (increased)

    In this example, there are 7 measurements that are larger than the previous measurement.
    """

    Synthesizing 9/10 solutions (Duplicates hidden)

    =======
    Suggestion 1

    import sys

    =======
    Suggestion 2

    def main():
        """
        Main function
        """
        with open("input", "r") as input_file:
            previous = int(input_file.readline())
            increases = 0
            for line in input_file:
                current = int(line)
                if current > previous:
                    increases += 1
                previous = current
            print(increases)

    =======
    Suggestion 3

    with open("input", "r") as f:
        lines = f.readlines()
        lines = [int(line.strip()) for line in lines]

        count = 0
        for i in range(1, len(lines)):
            if lines[i] > lines[i-1]:
                count += 1

        print(count)

  # Read an array from input.txt.

    # "Load" and "file" instead of more precise terms.
    def load_numbers(file):
        with open(file) as f:
            # both .strip() and .readlines() are redundant and should be removed.
            return [int(line.strip()) for line in f.readlines()]
        
    # Verbose and imprecise naming.
    def calculate_differences(numbers):
        numbers = sorted(numbers) # Inefficient cloning instead of .sort().
        differences = [numbers[0]] # Breaks on empty lists.
        for i in range(1, len(numbers)):
            differences.append(numbers[i] - numbers[i-1])
        differences.append(3) # Where did 3 come from?
        return differences

    # Vague. Redundancy with param name. Sounds too much like English.
    def count_increasing_numbers(numbers):
        increasing = 0
        for i in range(1, len(numbers)):
            # Homework looking if/else.
            if numbers[i] - numbers[i-1] == 1:
                increasing += 1
            else:
                increasing = 0 # Why would it reset?
        return increasing

    # "parse" and "filename" are more precise, and out params indicate higher performance code.
    def parse_numbers(filename, out_numbers):
        # Explicit file-mode!
        with open(filename, 'r') as f:
            # Reading lines by iterating over the file object!
            for line in f:
                # Explicit error handling!
                try:
                    # No redundant .strip()!
                    out_numbers.append(int(line))
                except ValueError:
                    pass

    # "get", "adjacent", and "diff" all show familiarity with vocabulary.
    def get_adjacent_diff(numbers):
        # Simple one liners! No off-by-1 errors!
        return [numbers[i] - numbers[i-1] for i in range(1, len(numbers))]

    # "Pairwise" is more technical, and avoiding name/arg redundancy. Less like English.
    def count_pairwise_increasing(numbers):
        # Another good one liner, making full use of list comprehension.
        return sum([1 for i in range(1, len(numbers)) if numbers[i] - numbers[i-1] == 1])