move.b #200,d0
move.b #100,d1
add.b d0,d1 ; 8th bit goes to X flag
subx.b d0,d0 ; d0 = $00 or $ff depending on X flag
or.b d0,d1 ; d1 = 255 if there was saturation
You can do the same with all others that somehow store
the 8th bit carry somewhere then allow using it for substraction.
IMO the first graph would make a lot more sense when plotted in log scale.
Also this way of framing "As of February 2026, the US dollar has lost 96.9% of its purchasing power relative to January 1914. This means that $100 in 1914 would buy only approximately $3.05 worth of goods today" is of course math-correct but difficult to understand intuitively.
I think it makes more sense to explain it in the opposite direction or in both directions: "$100 in 1914 would buy only approximately $3.05 worth of goods today, or equivalently, $100 in 1914 is worth ~ $3278 nowdays (because 100 / 3.05 ~= 32.78 "
This also makes it easier to understand that the term "millionaire == person that has 1 million USD" only makes sense around 1914, because the equivalent amount of wealth nowdays would be "millionaire == person that has 32 million USD"
You can do the same with all others that somehow store the 8th bit carry somewhere then allow using it for substraction.